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70p^2+58p+12=0
a = 70; b = 58; c = +12;
Δ = b2-4ac
Δ = 582-4·70·12
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-2}{2*70}=\frac{-60}{140} =-3/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+2}{2*70}=\frac{-56}{140} =-2/5 $
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